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67 Views

Question : Directions: Which term from among the given options can replace the question mark (?) in the following series to make it logically complete?
EZ 10, ?, ID 36, KF 49, MH 62

Option 1: HC 21

Option 2: FB 22

Option 3: GB 23

Option 4: FC 21

Team Careers360 24th Jan, 2024

Correct Answer: GB 23


Solution : Given:
EZ 10, ?, ID 36, KF 49, MH 62

Add 2 in the positional value of each letter and add 13 to each number of the previous term to get the next term –
EZ 10→E + 2 = G; Z + 2 = B; 10 + 13 = 23→GB 23
GB 23→G + 2 = I; B + 2 = D; 23 + 13 = 36→ID 23
ID 36→I + 2 = K; D + 2 = F; 36 + 13 = 49→KF 49
KF 49→K + 2 = M; F + 2 = H; 49 + 13 = 62→MH 62

So, the missing term in the series is GB 23. Hence the third option is correct.

17 Views

Question : Parts of the following sentence have been given as options. Select the option that contains a grammatical error.

Bobo was / very richer than Jim / as he had illicitly accumulated / all his wealth.

Option 1: very richer than jim

Option 2: all his wealth

Option 3: as he had illicitly accumulated

Option 4: Bobo has

Team Careers360 19th Jan, 2024

Correct Answer: very richer than jim


Solution : The first option is correct.

In the sentence provided, the error lies in the use of very with the comparative form of the adjective "rich". When making comparisons, adjectives like rich form their comparative and superlative degrees without the use of very.

Therefore, the correct sentence is: Bobo was richer than Jim, as he had illicitly accumulated all his wealth.

30 Views

mera class 12 me 57% aye the chemistry me grace marks Mila hai to me is year ree exam de raha hu but me neet ke exam me konsa marksheet du.

Rajib 19th Jan, 2024

Which board and how many grace marks did u got? If you're aggregate pcb is more than 50% then you're eligible don't worry about the grace mark that is given my every board in India except cbse and it is acceptable, reappearing 12th again will make you a private candidate,NMC doesn't want private candidate to appear for neet, every year this case gets hold on supreme court,so it's better if you don't give improvement exam if you already have pcb  50% combination

184 Views

i have+9 grace mark in chemistry can I give neet?

mjaisinghani62 13th Jan, 2024

Hello Rajib

You can appear for neet if you have passed in chemistry subject.

Also it is important that you must get minimum 50%  aggregate marks in physics,  chemistry and biology. This means your total marks in physics ,chemistry and biology should be 150 ( minimum) .

Now your marksheet must be showing 35 in chemistry so you must have secured minimum 115 marks in physics + biology to make the total 150 in three subjects .

Eligibility criteria to appear neet is that -

The candidate must have completed at 17 years of age on 31st December in the year when he / she is applying for neey.

The candidate must have secured minimum 50% marks in physics,  chemistry and biology .

English subject is also mandatory.


To know more  you may go through the link given below.

https://medicine.careers360.com/articles/neet-2024

828 Views

My Ews certificate is issued on 12 jan 2024 and it is valid for the year 2023-24. will it be valid for Neet 2024 form submission

Tanya Gupta 14th Jan, 2024

Hello,


Yes, since your EWS certificate is issued on January 12, 2024 and is going to be valid for the year 2023 -2024 which is a year. This means that it should be valid for NEET 2024 form submission. Since it is valid for the year 2023-24, it should cover the NEET 2024 application period as well.


I hope this helps,

Thank you

8 Views

Question : Directions: Four number pairs have been given, out of which three are alike in some manner and one is different. Select a different one.

Option 1: 8 – 512

Option 2: 2 – 8

Option 3: 3 – 9

Option 4: 9 – 729

Team Careers360 13th Jan, 2024

Correct Answer: 3 – 9


Solution : Let's check the options –
First option: 8 – 512; 83 = 512
Second option: 2 – 8; 23 = 8
Third option: 3 – 9; 33 = 27 ≠ 9
Fourth option: 9 – 729; 93 = 729

So, only in the third option, the cube of the first number is not equal to the second number. Hence, the third option is correct.

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