#IT
279 Views

A concave lens of glass, refractive index 1.5, has both surfaces of the samr radius of curvature R. on immersion in a medium of refractive index 1.75, it will behave as a...


manojdhami293 20th Jun, 2020
Answer (1)
Mounika Sonti 20th Jun, 2020

Hello!!!

Hope you are doing great!!!

Consider refraction of light from infinity at first surface,

μ 2/v - μ 1/u = μ 2- μ 1/R

1.5/v1 - 1.75/-∞   = 1.5-1.75/-R

Consider refraction of this image from second surface

1.75/v2 - 1.5/v1 = 1.75-1.5/R

v2=3.5R

The image of light coming from infinity.

It is converging since focal length is positive.

Hope it helps!!!

Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
VIT Bhopal University | M.Tec...
Apply
M.Tech admissions open @ VIT Bhopal University | Highest CTC 52 LPA | Apply now
Amity University | M.Tech Adm...
Apply
Ranked amongst top 3% universities globally (QS Rankings).
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Great Lakes PGPM & PGDM Admis...
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.3 LPA Avg. CTC for PGPM 2024
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books