a gas at 10c temperature and 1.013 ×10^3 pa pressure is compressed adiabatically to half of it's volume. if the ration of specific heats of the gas is 1:4 , what is it's final temperature

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a gas at 10c temperature and 1.013 ×10^3 pa pressure is compressed adiabatically to half of it's volume. if the ration of specific heats of the gas is 1:4 , what is it's final temperature

srijabogavally 17th Jul, 2020

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Answer (1)

pjinendraBTECH19 17th Jul, 2020

First Convert Temp deg Celsius to kelvin

T1 = 10deg c + 273K = 283 k

Volume is half then

V2 = V1/2

Gama is 1.4

So equation is T1 V1^gama-1 = T2 V2^gama -1

then T2 = T1 x (v1/v2)^gama-1

so T2 = 283 x (V1/(v1/2))^1.4-1

T2 = 283 x 2^0.4

T2 = 373.42K

to Kelvin to deg cel

T2 = 100.42 deg cel

Hope its Help!!

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