A takes 2 hours more then the B to walk d km,but if A doubles his speed,then he can make it in 1 hour less then B.How much time does B require for walking d km
Answer (1)
8th May, 2022
Hi,
Suppose B takes t hours to walk d km.
Then, A takes (t + 2) hours to walk d km.
With double speed, A will take 21(t+2) hours.
∴t−21(t+2)=1⇒2t−(t+2)=2⇒t=4
∴ B takes 4 hours to walk d km.
OR
Let time take by B to walk D km = T
Time taken by A to walk D km = (T +2).
Since, ST = D. When distance is constant, Speed is inversely proportional to time taken, means if speed become double, time taken would become half.
So,
In second case time taken by A = (T +2)/2.
Now, this time A takes 1 hr less than B.
(T +2)/2 = T-1
T +2 = 2T - 2
T = 4 hours.
Hope this helps.
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