145 Views

evaluate integral of 1/sin^2x+cos^x with respect to x


MASTER TECHY IN KANNADA 12th Apr, 2021
Answer (1)
Jainshahajal 12th Apr, 2021

Hello Aspirant,

Hope you are doing well.

Integral of 1 / (sin power 2x + cos power 2x) . It is quite difficult to write here. But I'm trying my best.

there is no integration or power sign so we represent these sign with some other sign.

| represent the integration, and

** represent the power sign

when you can do this in notebook please change these sign with integration and power.

we know that,

sin**2x + cos **2x = 1

= (sin**2x + cos**2x) / (sin**2x cos**2x) = [ ( 1 / cos**2x) + ( 1 / sin**2x) ]

= sec**2x + cosec**2x

then, | ( 1 / (sin**2x cos**2x) dx

= | (sec**2x dx ) + | (cosec**2x) dx + C

= tan x - cot x + C

I hope you can understand.

All the best.

2 Comments
Comments (2)
13th Apr, 2021
thanks
Reply
13th Apr, 2021
MASTER TECHY IN KANNADA There is a addition symbol in denominator but you used multiplication symbol
Reply

Related Questions

Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
UPES | BBA Admissions 2025
Apply
#41 in NIRF, NAAC ‘A’ Grade | 100% Placement, up to 30% meritorious scholarships | Last Date to Apply: 28th Feb
MAHE Manipal M.Tech 2025
Apply
NAAC A++ Accredited | Accorded institution of Eminence by Govt. of India | NIRF Rank #4
Sanskriti University LLM Admi...
Apply
Best innovation and research-driven university of Uttar Pradesh
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books