The distance AB = $((1-0)^2 + (0-0)^2 + (2-0)^2)^(1/2)$
AB = $(5)^(1/2)$
Question : If the phase difference between two points is 1200 for a wave with a velocity of 360 m/s and a frequency of 500 Hz, then the path difference between the two points is:
Option 1: 1 cm
Option 2: 6 cm
Option 3: 12 cm
Option 4: 24 cm
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile