Hello sir, I'm a general category boy who appeared for jee Mains paper 2 and I scored 91.86 percentile. I would like to know my general rank

Hello Ayush,

First of all congratulations on getting above 90 percentile. Now, let me tell you about the probable rank that your percentile score might be able to fetch you. Since approximately around 1.45 lakh students appeared for JEE B. Arch exam so the rank can be predicted from the given formula -

(100- your total percentile score) * 1,45,386/ 100.

So, accordingly, when calculated, your rank might be somewhere around 11,834 - 11,835. But, this is a rough evaluation so it is best that you wait for the final rank list that is to be announced by NTA. Along with the result of JEE Main Paper-2 April session, authorities will also release the rank list.

If you wish to score better, do not worry, you have another chance in the April session. So, start preparing for the April session of the exam and the best of the two scores will be taken into account.

For more details about the colleges that you might get, you can go through the following link which gives you previous year opening and closing ranks of various colleges-

Https://engineering.careers360.com/articles/jee-main-paper-2-result

Hope this helps.

Good luck!

https://www.google.com/url?q=https://engineering.careers360.com/articles/jee-main-paper-2-result&sa=D&source=hangouts&ust=1549084940225000&usg=AFQjCNEPL3X7V10jZotLhTI-ceCB3tm35g

Use this link for JEE B.Arch.

Total 1.45 Lakh students appeared for the exam and hence rank out of percentile can be found.

11,834 is your general rank

Congratulations and thankyou