jee main me 86.5793923 toh kya hme. hbit kanpur mil skta h
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hi priya,
I hope you are doing well. For a percentile of 86.5793932 your CRL rank will be around 1.35 Lakh. With this 1.35 lakh if you are general candidate then you cannot get any branch in HBTU Kanpur. For admission in HBTU Kanpur you would have need at least rank of 80 thousand or a percentile greater than 92.
I hope this answer will help.
All the best for the future!!
Hey!
The link of college predictor by Jee mains 2020 is given below which will show you the good colleges/universities for which you are eligible. Just enter your percentile and other required details.
Thank you.
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55% jee me aaye h to nit mil skta h kya
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