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Length of a simple pendulam is 1m when its bob is at its lowest point it's velocity 7 m/s if the bob leaves it's circular path at a height h above the center of the circle then the value of h is


Dasi Srinu 27th Mar, 2025
Answer (1)
sadafreen356 28th Mar, 2025

To find the value of h, we need to use the concept of conservation of energy. At the lowest point, the bob has kinetic energy due to its velocity. As it rises, this kinetic energy is converted into potential energy.


Initial kinetic energy (KE) = (1/2)mv^2, where m is the mass of the bob and v is its velocity.


At the highest point, the bob has potential energy (PE) = mgh, where g is the acceleration due to gravity and h is the height above the center of the circle.


Since energy is conserved, KE = PE:


(1/2)mv^2 = mgh


Given:


- v = 7 m/s

- g = 9.8 m/s^2 (approximately)


Now, we can solve for h:


h = (1/2)v^2 / g

= (1/2)(7)^2 / 9.8

= 2.5 m


However, this is the total height from the lowest point. Since the length of the pendulum is 1m, the height above the center of the circle (h) would be:


h = 2.5 - 1

= 1.5 m


So, the value of h is approximately 1.5 meters.

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