Mathews and Noel together can complete a piece of work in 63 days they started the work and after 27 days Mathews left and Noel complete the remaining work in 60 days in how many days Mathews complete the work
Answer (1)
Student Expert
27th Mar, 2020
Hi!
Solution of your query is given below :
Work done by matthews and Noel in 63 days = [(1/63)*27]= 3/7
Remaining work = 1-3/7 =4/7
Now, 4/7 work is done by Noel in 60 days
Therefore, whole work will be done by Noel in 60*(7/4)= 105 days
Hope it helped to clear your delimma.
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