2384 Views

The value of acceleration due to gravity at a point P inside the earth and at another point Q outside the earth is g/2. Maximum possible distance in terms of radius of earth R between P and Q is


Akash Deep 5th Jan, 2020
Answer (1)
Rishi Garg 5th Jan, 2020

The value of acceleration due to gravity at some height is given by

g1 = g*((R/R+h)^2)

Where h is the height of the particle (Q, outside the earth).

Value of acceleration due to gravity inside the earth is given by

g1 = g*(1-d/R)

where d is the depth of the particle (P, inside the earth)

putting g1 = g/2 in both the cases, you will get value of h and d.

adding both h and d, you will get the maximum possible distance in terms of radius of earth.

1 Comment
Comments (1)
5th Jan, 2020
yes u r r8 but pls.tell the r8 answer. its coming (R(2^3/2-1))/2 but answer is given (R(2^3/2+1))/2
Reply

Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
VIT Bhopal University | M.Tec...
Apply
M.Tech admissions open @ VIT Bhopal University | Highest CTC 52 LPA | Apply now
Amity University | M.Tech Adm...
Apply
Ranked amongst top 3% universities globally (QS Rankings).
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books