The vapour density of N2O4 at a certain temp is 30. What is the percentage dissociation of N2O4 At this temp?

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The vapour density of N2O4 at a certain temp is 30. What is the percentage dissociation of N2O4 At this temp?

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Akshay Priyadarshi 18th Sep, 2017

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akash soni 19th Sep, 2017

N2O4 ---------NO2. Initially N2O4 has conc.= 1 then at equilibrium N2O4 has conc.1-X. And NO2 has conc. =2x initially we have taken N2O4 =1 Molar mass =92 .V.D at eq.=30 .M.w.=60.

n initial/ n final =M final/M initial

1/1-X+2X=60/92

1/1+X=60/92

1+X=92/60

X=92/60 -1

X=32/60

X=0.53 percentage dissociation=0.53 X 100=53

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Arnab Ghosh 18th Sep, 2017

Solving related questions ask on Byjus, Meritnation etc. It's not a educational site, it's carrer counselling site

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AJ TOPPER 18th Sep, 2017

Only Career related questions should be asked..,

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