When working individually A and B takes 6days and 8days to paint the fence respectively. They started working together. After 2 days C also joined them. If the work was completed after 1 day together(total 3 days). In how many days can C do the same all alone.
Answer (1)
21st Jul, 2021
Hello Student,
First of all, Work = Time * Rate
Let the total work to be 48 Units.
So, Rate of A = 48/6= 8
Rate of B = 48/8 = 6
Rate for (A+B) i.e. when they work together = 8+6 = 14
They worked for 2 days,
So, work completed will be = 14*2 = 28
Work left = 48 -28 = 20
Now, they all worked together (A+B+C) for 1 day to complete the work i.e. 20 units
So, Rate (A+B+C) = 20/1 = 20
Rate of C = Rate (A + B+ C) - Rate (A + B) = 20-14 = 6
So, C alone can do the work in = 48 / 6 = 8 days
Hope this Helps!
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