Hello Student,
First of all, Work = Time * Rate
Let the total work to be 48 Units.
So, Rate of A = 48/6= 8
Rate of B = 48/8 = 6
Rate for (A+B) i.e. when they work together = 8+6 = 14
They worked for 2 days,
So, work completed will be = 14*2 = 28
Work left = 48 -28 = 20
Now, they all worked together (A+B+C) for 1 day to complete the work i.e. 20 units
So, Rate (A+B+C) = 20/1 = 20
Rate of C = Rate (A + B+ C) - Rate (A + B) = 20-14 = 6
So, C alone can do the work in = 48 / 6 = 8 days
Hope this Helps!
Question : A alone can do a work in 14 days. B alone can do the same work in 28 days. C alone can do the same work in 56 days. They started the work together and completed the work such that B was not working in the last 2 days and A did not work in the last 3 days. In how many days
Question : A alone can do a work in 11 days. B alone can do the same work in 22 days. C alone can do the same work in 33 days. They work in the following manner: Day 1: A and B work. Day 2: B and C work. Day 3: C and A work. Day 4: A and B work. And so on.
Question : A can do $\frac{1}{3}$rd of a piece of work in 32 days, B can do $37 \frac{1}{2}$% of the same work in 24 days, while C can do 60% of the same work in 48 days. B and C together started and worked for x days. After x days, B left and A joined C and together, completed the
Question : A can-do $\frac{1}{5}$ of a piece of work in 20 days, B can do 30% of the same work in 36 days, and C can do 80% of the same work in 160 days. B and C together started and worked for x days. After x days B left the work, and A joined C and both completed the remaining work in
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile