Kurukshetra University All Questions

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Dear Nitish ,

No problem ,but if you have dropped out due to some reason then you must be start from the starting if you wants to take admission again .Fist you have to purse entrance test Jee then at the time of counselling they might be ask whats the reason behind you dropped out ,so you can explain your problem .But it will not impact on your  counselling .

I hope it will helpful and best of luck

Thanks

hey,

kurukshetra university , kurukshetra do  not offer any honour course what they do offer is listed below

1. B.E/B.Tech

2. B.S.c

3. M.E/M.Tech

4. B.Com (//B.Com)

5. M.A.

6. B.A.

Hope this helps!

Hello,

Your rank will be around 2,60,703 and the formula is (100-your total percentile)*869010/100 where 869010 is the total number of candidates appeared in January session.And category rank will be in between 15000-20000.In 2019 the round 7 cut off for Home state SC candidate for Mechanical Engineering was 5517, for electrical it was 5209 and for ECE it was 3984.Considering this you may not get seat, you need to score 92 or above percentile to get rank around 3000 and to get rank around 5000 your percentile must be 86 or above.Cut off is subjected to change it may increase or decrease depending on number of seats available, number of candidates appeared etc.

You may predict the colleges https://engineering.careers360.com/jee-main-college-predictor

Hello!!!!

Hope you are doing great!!!!

Kartik,Your All India Rank would be 104281 approximately,calculated by using the formula 100-88*869010/100 where 88 is your percentile and 869010 is the number of candidates appeared for jee mains in january session.As per the previous year scenario,it would be difficult to get seat in NIT Kurukshetra.You may have to appear for July session .For checking the probabilities of the colleges,you can use our college predictor.Link is provided below:

https://engineering.careers360.com/jee-main-college-predictor?ici=cp-listing_engineering&icn=JEE-Main-College-Predictor If you are looking for preparing for Jee mains,you can try our knockout package:

https://learn.careers360.com/knockout-jee-main-april/

you can check the previous year cutoff's in the link provided below:

https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-kurukshetra

Hope it helps you!!!

Good luck!!!!

Hello,
To get a seat in NIT Kurukshetra, you must score above 130 marks in JEE mains to be on the safe side. As you are from SC category, you will get quite some benefits. Also you need to score above 65% in your class 12 boards to be eligible for admission into NITs.

Here's a detailed information about the previous year cutoffs for various branches in NIT Kurukshetra. https://www.google.com/url?sa=t&source=web&rct=j&url=https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-kurukshetra/amp&ved=2ahUKEwjk7a_41vbpAhXnxzgGHcUtCbYQFjAIegQIBBAB&usg=AOvVaw1nhaehrAjkCIS7Ud-1zyuJ&ampcf=1

Hope it helps

Entrance Test will be of the level of qualifying examination. There shall be 50 objective multiple choice type questions of 2 marks each for 1 hour duration. You'll be awarded 2 marks for every correct answer. There will be no negative marking. The syllabus will be same as the last year.
The syllabus is as follows-

• Classical mechanics and theory of relativity
• Electricity, Magnetism and Electromagnetic theory
• Properties of Matter and Kinetic Theory of Gases
• Semiconductor Devices
• Thermodynamics
• Waves and Optics
• Statistical Physics
• Quantum Physics
• Nuclear Physics
• Solid State Physics
• Atomic and Molecular

Hello,

Cut off is given in terms of closing rank and opening rank for each category and branch.In 2019 the round 6 cut off was follows for SC home state category for various branches

• EE: 5209
• Civil: 5581
• Production: 7231
• IT: 2004
• Computer: 1521
• Mechanical: 5432
• ECE: 3894

It is difficult to give the exact percentile.But according to the number of candidates appeared in JEE Main January 2020 session you need to score 90-95 percentile to get such rank as in 2019 round 6 cut off rank.But cut off changes in 2020 depending on number of candidates appeared, seats available in each branch etc.

Please try our JEE main knockout program

https://learn.careers360.com/knockoutfull-jee-main-april/?icn=JEE_Main_knockout&ici=c360_sticky_qna_engineering

Hello dear

First of all in 2016 there was no such percentile system. This system is adopted from last year .

And when we calculate your approximately rank it will come out nearly 16000-20000 in school category and it will be more than 2 lakhs in general category and with this rank it will be not possible to get admission in NIT KURUKSHETRA because as this is the very good and one of the best NIT.

Here I am giving you the link where you can see last year's cut offs :

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-nit-kurukshetra/amp

Good luck

Hello,

You have not mentioned your percentile.In 2019 these were the cut off SC home state category branch wise in round 7 JoSAA counselling in NIT, Kurukshetra

• CSE: 1521
• Production and Industry Engineering: 7597
• IT: 2004
• Mechnaical : 5517
• ECE: 3894
• Civil: 6282
• EE: 5209

To get such rank you need to score 95 or above percentile.Cut off may increase or decrease in 2020.Cut off depends on number of candidates appeared, difficulty level of exam, number of seats available etc.