Saveetha Engineering College, Chennai All Questions

Hello ManishaDevi

Total fees for BE course is around 1.25 lakhs per annum. If you consider the quality of Education and other things like Faculties and Campus life then fees is little bit more than other colleges. There are various other colleges affiliated with ANNa Univ, that too with less fees and better quality of Education.

For more info: https://dqxeclau.top/colleges/saveetha-school-of-engineering-chennai

Which cut off you are talking about

Hi,

The official website of the Saveetha College of engineering shows that it is  not provide course like BCA, it has Be/b.tech/pg/M.s research /ph.d/Mba.

Hello dear student !

Please elaborate your question more and rewrite it with more explanation so that we can answer your query more properly.

Dear aspirant

Average acceleration is  change in velocity upon change in time.

Therefore

Acceleration= v÷t

=20÷5

=4   will be average acceleration.of car as per your question.

Thank you

Hello,

First get your concepts clear, you can start off with Grammar, learn all the important topics such as Subject-Verb Agreement, Preposition, Noun, Pronoun, Adjective, Adverb, Active & Passive Voice, Narration etc. You can go through Wren and Martin for this, Having a strong foundation on grammmar will enable you to solve sentence reaarangement, fill in the blanks, error detection etc,

You can work on your vocabulary by reading any newspaper or going through Word Power Made Easy, it's a wonderful book for vocabulary.

Once you have gone through aforementioned steps, then try solving any English Book, you can choose between Plinth to Paramount or SP Bakshi. Along with this, go through previous year papers, anaylse on a regular basis.

Hello,

We know that, as per the Equation of Motion,

s = ut + 0.5 a t^2

So, for first 3 sec.,

10 = 3u + 0.5 x a x 9

So, 3u + 4.5a = 10.............. ( 1 )

Now, for next 4 sec.,

25 = 7u + 0.5 x a x 49

So, 7u + 24.5a = 25............ ( 2 )

Solving ( 1 ) and ( 2 ), we get,

a = 0.12 m/s^2 and u = 3.15 m/s

Now, also as per the Equation of motion,

v = u + at

So, For 8 sec.,

v = ( 3.15 ) + ( 0.12 x 8 )

So, v = 4.11 m/s

Hence, The velocity of object at the end of 8 seconds will be 4.11 m/s

Best Wishes.