Hey,

As far as I know  the reservation certificate is mandatory to be submitted or presented at the time of admission in all courses or college. Failure in presenting your category certificate may results in cancelling  of your reservation for that college.

You may be considered in unreserved category or in worse case you may be debarred from the admission process due to incapable of presenting the correct proofs for your details filled in the application form.

Hope that helps.

Thank you.

hi,

see master of science in mathematics is a conventional course where the 90% syllabus is application of mathematics , chapters relating with complex analysis, real analysis, theory and formation of formulas. where msc in mathematics and computing syllabus has software programming to analysis of different types of complex data, data science, data base courses.

in the current situation of job prospect there is more scope in Industry for msc in mathematics and computing degree holders.

Hello,

In order to be eligible to for CSIR UGC NET 2020 the candidate of general (UR) / general-EWS and OBC candidate must hold a B. Tech  with at least 55% marks.  The maximum age limit for Joint Research Fellowship is 28 years as on July 1, 2020 as per the eligibility criteria of CSIR UGC NET 2020 for post of Assistant Professor/Lecturers there is no Age limit.

Hello! Warm greetings!

According to eligibility criteria for CSIR NET, you can have multiple attempts and there is no restriction on that. However, in order to give the test you must one of PG degree/ MBBS / BS-4 years/ B.Pharma/ B.E or B.Tech degree or any other quivalent degree with the minimum marks of 55% for general and OBC category and 50% for SC/ST?PWD. Also, there is an age limit. i.e, maximum of 28 years for JRF whereas no age limit for lectureship.

All the best.

Hello,

CSIR UGC NET June 2020 Exam will be conducted by the National Testing Agency (NTA) on 21st June 2020 for determining the eligibility of Indian Nationals for the award of Junior Research Fellowships (JRF) and for determining eligibility for Lectureship (LS)/Assistant Professorship in certain subject areas falling under the faculty of Science & Technology like Chemical Sciences, Earth, Atmospheric, Ocean and Planetary Sciences, Life Sciences, Mathematical Sciences and Physical Sciences.

Good Luck.

CSIR-UGC Test is conducted for determining eligibility for appointment as Lecturer (LS) and for determining the eligibility of Indian Nationals for the award of Junior Research Fellowships (JRF)

UGC NET 2020 is conducted for five subjects

- Chemical Sciences

, Earth, Atmospheric

Ocean and Planetary Sciences,

Life Sciences,

Mathematical Sciences,

Physical Sciences.

CSIR-UGC NET 2020 is a MCQ-based exam. There will be negative marking for wrong answers

you can find syllabus and previous year question papers easily on the link given below.

https://competition.careers360.com/articles/csir-ugc-net-syllabus

hey,

eligibility for CSIR NET 2020 is candidate must hold a degree in B.Tech/B.E/B.pharma /MBBS/BS (4years)/integrated BS-MS/M.Sc and candidate must have secured a minimum aggregate of 55 percent marks in their graduation and  c candidate belonging to SC/ST and persons with disability (PWD) need to score 50 percent marks in M.Sc or equivalent degree/integrated BS-MS/BS- (4 years)/BE/B.tech/B.pharma/MBBS, and candidate who have enrolled theirselves for M.Sc or have completed their graduation can also apply for the same under result awaited (RA) category but on one condition they will have to complete the qualifying degree with required marks within two years to get the fellowship from the effective date of award.

for more information you may refer to the link

https://competition.careers360.com/articles/csir-ugc-net

good luck!

Hey Sapna

For CSIR NET LIFE SCIENCE questions and answers you can visit https://competition.careers360.com/articles/csir-ugc-net-question-papers

They have many other papers on life science like this and it will be beneficial for you to solve them. Also  you can take online classes on Unacademy (it is helpful). All the best.