Vector Addition And Vector Subtraction

Vector Addition And Vector Subtraction

Vishal kumarUpdated on 02 Jul 2025, 05:35 PM IST

Vectors are fundamental elements in physics and mathematics, representing quantities that have both magnitude and direction. Unlike scalar quantities, which can be simply added or subtracted using basic arithmetic, vector operations require special consideration of their directional components. Understanding vector addition and subtraction is essential for accurately describing physical phenomena such as forces, velocities, and displacements.

This article delves into the methods for combining and resolving vectors, starting with the straightforward cases of vectors in the same direction and progressing to more complex scenarios involving different directions, employing the triangle and parallelogram laws of vector addition.

Vector Addition

  • Vector quantities are not added according to simple algebraic rules, because their direction matters.
  • The addition of vectors means determining their resultant.
  • When two vectors are in the same direction then upon addition the direction of the resultant vector is the same as any of the two vectors, while the magnitude of the resultant vector is simply the algebraic sum of two vectors.
  • eg, Vector $\vec{A}$ has magnitude $4 \&$ vector $\vec{B}$has magnitude 2 in the same direction.

$ \vec{A}+\vec{B}=4+2=6 $

So resultant has a magnitude equal to 6 while its direction is either along $\vec{A}$ or $\vec{B}$

Vector Subtraction

  • Vector subtraction of $\vec{B}$ from $\vec{A}$ is equal to Vector addition of $\vec{A}$ and negative vector of $\vec{B}$.
    $
    \vec{A}-\vec{B}=\vec{A}+(-\vec{B})
    $
  • E.g., Vector \vec{A} and \vec{B} are in the east direction with magnitudes 4 and 2 respectively.

Vector subtraction of $\vec{B}$ from $\vec{A}$ is equal
$
=\vec{A}-\vec{B}=4-2=2
$

The resultant vector has a magnitude of 2 in the east direction.

Now, let’s understand the different scenarios when both vectors do not have the same direction then the triangle law of vector addition and the Parallelogram law of vector addition come into play.

Triangle law of Vector Addition

If two vectors are represented by both magnitude and direction by two sides of a triangle taken in the same order then their resultant is represented by side of the triangle.


The figure represents the triangle law of vector addition So, the resultant side C is given by

$
c=\sqrt{a^2+b^2+2 a b \cos \theta}
$

Where $\theta=$ angle between two vectors.

Parallelogram law of Vector Addition

If two vectors are represented by both magnitude and direction by two adjacent sides of a parallelogram taken from the same point then their resultant is also represented by both magnitude and direction taken from the same point but by the diagonal of the parallelogram.

The figure represents the law of parallelogram Vector Addition

Commutative law

The Sum of vectors remains the same in whatever order they may be added.

$\vec{P}+\vec{Q}=\vec{Q}+\vec{P}$

Fig shows the Commutative law of vector addition.

Solved Example Based On Vector Addition And Vector Subtraction

For More Information On Vector Addition And Vector Subtraction, Watch The Below Video:

Now let’s understand the above law by some solved examples.

Example 1: The resultant of two forces 3P and 2P is R. If the first force is doubled, then the resultant is also doubled. The angle between the forces is

1) $120^{\circ}$
2) $60^{\circ}$
3) $180^{\circ}$
4) $90^{\circ}$

Solution:

From the triangle law of vector addition

So using the concept,

$
\begin{aligned}
& R^2=(3 P)^2+(2 P)^2+2 \cdot(3 P) \cdot(2 P) \cdot \cos \theta \\
& R^2=13 P^2+12 P^2 \cos \theta ....... (1)
\end{aligned}
$

When the first force is doubled, the resultant is doubled
$
\begin{aligned}
& \text { So, }(2 R)^2=(6 P)^2+(2 P)^2+2 \cdot(6 P)(2 P) \cdot \cos \theta \\
& \Rightarrow 4 R^2=36 P^2+4 P^2+24 P^2 \cos \theta \\
& \Rightarrow R^2=10 P^2+6 P^2 \cos \theta ............(2)
\end{aligned}
$

Equating (1) and (2)
$
\begin{aligned}
& \Rightarrow 13 P^2+12 P^2 \cos \theta=10 P^2+6 P^2 \cos \theta \\
& \Rightarrow 3 P^2=-6 P^2 \cos \theta \\
& \Rightarrow \cos \theta=-\frac{1}{2} \text { or } \theta=120^{\circ}
\end{aligned}
$

Equating (1) and (2)

$\begin{aligned}
& \Rightarrow 13 P^2+12 P^2 \cos \theta=10 P^2+6 P^2 \cos \theta \\
& \Rightarrow 3 P^2=-6 P^2 \cos \theta \\
& \Rightarrow \cos \theta=-\frac{1}{2} \text { or } \theta=120^{\circ}
\end{aligned}$

Hence, the answer is the option (1).

Example 2: The ratio of maxium and minimum magnitudes of the resultant of two vectors \text { }|\vec{a}| \text { and }|\vec{b}| is 3:1, Now |\vec{a}|=

1) $\mid \vec{b}$
2) ($2 \mid \vec{b}$
3) $3 \mid \vec{b}$
4) $4|\vec{b}|$

Solution:

$
\begin{aligned}
& |\vec{a}+\vec{b}|=\sqrt{a^2+b^2+2 a b \cos \theta} \\
& |\vec{a}+\vec{b}|_{\max }=a+b{ }_{\text {when } \theta=0^{\circ}} \\
& |\vec{a}+\vec{b}|_{\min }=a-b \quad \text { when } \theta=180^{\circ}
\end{aligned}
$
here
$
\frac{a+b}{a-b}=\frac{3}{1}
$
or
$
a+b=3 a-3 b
$
or $2 a=4 b \Rightarrow a=2 b$
$
|\vec{a}|=2|\vec{b}|
$

Hence, the answer is option (2).

Example 3:

Two vectors $\vec{A}$ and $\vec{B}$ have equal magnitudes. The magnitudes of $(\vec{A}+\vec{B})$ is 'n' times the magnitudes of $(\vec{A}-\vec{B})$. The angle between $\vec{A}$ and $\vec{B}$ is :

1) $
\sin ^{-1}\left[\frac{n-1}{n+1}\right]
$
2) $ \cos ^{-1}\left[\frac{n^2-1}{n^2+1}\right]
$
3) $ \sin ^{-1}\left[\frac{n^2-1}{n^2+1}\right]
$
4) $\cos ^{-1}\left[\frac{n-1}{n+1}\right]
$

Solution:

$\begin{aligned}
& A^2+B^2+2 A B \cos \theta=n^2\left(A^2+B^2-2 A B \cos \theta\right) \\
& \because|\vec{A}|=|\vec{B}| \\
& \therefore A^2+A^2+2 A^2 \cos \theta=n^2\left(A^2+A^2-2 A^2 \cos \theta\right) \\
& 2 A^2(1+\cos \theta)=2 A^2 n^2(1-\cos \theta) \\
& \cos \theta\left(1+n^2\right)=n^2-1 \\
& \cos \theta=\frac{n^2-1}{n^2+1} \\
& \theta=\cos ^{-1}\left(\frac{n^2-1}{n^2+1}\right)
\end{aligned}$

Hence, the answer is the Option (2)

Example 4:

The magnitude and direction of the resultant of two vectors $\vec{A}$ and $\vec{B}$ in terms of their magnitudes and angle $\theta$ between them is :

1) $
R=\sqrt{A^2+B^2-2 A B \cos \theta}, \tan \alpha=\frac{B \sin \theta}{A+B \cos \theta}
$
2) $
R=\sqrt{A^2+B^2+2 A B \cos \theta}, \tan \alpha=\frac{B \cos \theta}{A+B \sin \theta}
$
3) $
R=\sqrt{A^2+B^2-2 A B \cos \theta}, \tan \alpha=\frac{A \sin \theta}{B+A \sin \theta}
$
4) $
R=\sqrt{A^2+B^2+2 A B \cos \theta}, \tan \alpha=\frac{B \sin \theta}{A+B \cos \theta}
$

Solution:

In the Parallelogram law of vector addition

If two vectors are represented by both magnitude and direction by two adjacent sides of a parallelogram taken from the same point then their resultant is also represented by both magnitude and direction taken from the same point but by the diagonal of the parallelogram.

The figure given below represents the law of parallelogram vector Addition.

$\vec{R}=\vec{A}+\vec{B}$

Using Pythagorean theorem in triangle MOP-

$\begin{aligned}
& R^2=(B \sin \Theta)^2+(A+B \cos \Theta)^2 \\
\Rightarrow & R=\sqrt{A^2+B^2+2 A B \cos \Theta} \\
\Rightarrow & \tan \alpha=\frac{B \sin \Theta}{A+B \cos \Theta}
\end{aligned}$
Hence, the answer is option (4).

Example 5: Two forces P and Q, of magnitude 2F and 3F, respectively, are at an angle \theta with each other. If the force Q is doubled, then their resultant also gets doubled. Then the angle \theta (in degrees) is :

1) 0

2) 120

3) 90

4) 110

Solution:

Parallelogram law of vector addition -

If two vectors are represented by both magnitude and direction by two adjacent sides of a parallelogram taken from the same point then their resultant is also represented by both magnitude and direction taken from the same point but by the diagonal of the parallelogram.

- wherein

$
R^2=P^2+Q^2+2 P Q \cos \theta
$

Represents the law of parallelogram Vector Addition
Case 1
$
R^2=4 F^2+9 F^2+12 F^2 \cos \theta
$

Case 2
$
\begin{aligned}
& 4 R^2=4 F^2+36 F^2+24 F^2 \cos \theta \\
& 16 F^2+36 F^2+48 F^2 \cos \theta=4 F^2+36 F^2+24 F^2 \cos \theta \\
& \therefore 12 F^2=-24 F^2 \cos \theta \\
& \theta=120^{\circ}
\end{aligned}
$
Hence, the answer is option (2).

Summary

Understanding vector addition and subtraction is crucial for accurately analyzing physical phenomena involving directional quantities. By mastering the methods for combining vectors, whether in the same or different directions, one can effectively apply these concepts to solve complex problems in physics and engineering, utilizing the triangle and parallelogram laws of vector addition

Frequently Asked Questions (FAQs)

Q: What is the concept of a displacement vector, and how does it relate to vector addition?
A:
A displacement vector represents the change in position from an initial point to
Q: How does vector addition apply to analyzing magnetic flux?
A:
Magnetic flux is a scalar quantity, but it's calculated using the dot product of the magnetic field vector and the area vector. When dealing with multiple magnetic fields or complex surfaces, vector addition of the magnetic field vectors is necessary before calculating the flux. This concept is crucial in electromagnetism and electrical engineering.
Q: What is the significance of the associative property in vector addition?
A:
The associative property of vector addition states that (A + B) + C = A + (B + C), where A, B, and C are vectors. This property allows flexibility in the order of adding multiple vectors, which is particularly useful in simplifying complex addition problems or in proving vector relationships.
Q: How does vector addition apply to electromagnetic fields?
A:
In electromagnetism, the total electric or magnetic field at a point due to multiple sources is found by vector addition of the individual fields produced by each source. This principle, known as superposition, is crucial for analyzing complex electromagnetic systems and understanding phenomena like interference and diffraction.
Q: How does vector addition apply to analyzing complex motion?
A:
In analyzing complex motion, like projectile motion or circular motion, vector addition is used to combine different components of motion. For example, in projectile motion, the horizontal and vertical components of velocity are treated separately and then combined using vector addition to determine the overall motion of the projectile.
Q: How does vector addition apply to calculating electric potential?
A:
While electric potential is a scalar quantity, it's calculated from the electric field, which is a vector. The total electric potential at a point due to multiple charges is the scalar sum of the potentials due to each charge. This involves vector operations in the calculation of the electric field before summing the potentials.
Q: What is the concept of a resultant vector, and how is it determined?
A:
A resultant vector is the single vector that represents the combined effect of two or more vectors. It is determined through vector addition, either graphically (using methods like the parallelogram or tip-to-tail) or algebraically (by adding vector components). The resultant summarizes the overall effect of multiple vectors acting together.
Q: How does vector addition apply to calculating torque?
A:
While torque itself is calculated using the cross product, vector addition is used when multiple torques act on a system. The net torque is the vector sum of all individual torques. This principle is crucial in rotational dynamics and the analysis of equilibrium in static systems.
Q: What is the concept of vector components, and how do they simplify addition?
A:
Vector components are the projections of a vector onto the coordinate axes. Breaking vectors into components simplifies addition by allowing you to add corresponding components separately. This method is particularly useful when dealing with non-perpendicular vectors or multiple vectors in complex arrangements.
Q: How does vector addition apply to momentum in quantum mechanics?
A:
In quantum mechanics, momentum is treated as a vector quantity. The total momentum of a system of particles is the vector sum of the individual momenta. This concept is important in understanding conservation laws at the quantum level and in analyzing particle interactions.