Hi

It is difficult to make prediction as cut off keeps changing every year  depending upon various factors like

------------) number of students that appeared in the neet exam,

------------) kind of marks obtained by them ,

------------)  toughness level of the neet examination

------------)  number of seats available

------------) the category you are from etc

Anyway,

when we go through previous year trends

>>>>>> With  417 marks,

You have good chances in deemed universities for mbbs which are listed below along with their cut off marks in neet 2020,2nd round all india counselling conducted  for 100 % deemed university seats   :-

----------) B.L.D.E University, Bijapur:- 387 marks

----------) MGM Medical College, Navi Mumbai:- 380 marks

----------) Institute of Medical Sciences and SUMH, Bhubaneswar:-360 marks

----------) Sri Siddhartha Medical College DU, T Begur:- 328 marks

----------) BVDU Medical College and Hospital, Sangli:- 311 marks

----------) Saveetha Medical College, Chennai:- 265 marks

----------) Dr. DYP Edu. Soc. Deemed Uni., Kolhapur:- 262 marks

And a few more

Deemed universities are known for high fee, the average fee in these deemed universities would be roughly around 15 to 20 lacs per annum

This has been  predicted on the basis of previous years data  but  cutoff keeps changing so to have clear picture of the complete list of colleges in which you have chances, you can go through our college predictor at

https://medicine.careers360.com/neet-college-predictor?icn=QnA&ici=qna_answer

With the help of predicted colleges you can make better choice while filling your choices of colleges during your counselling

To help in your counselling, we have mbbs companion in which in addition to college predictor tool you also get information regarding various counselling i. e all india , deemed, central and state  counselling and you get to attend live webinars with experts to guide you and get all your doubts cleared. The link is given below:-

https://dqxeclau.top/mbbs-companion?utm_source=qna

Thank you