I want to study B. Tech Biotechnology in IIT, Kharagpur. What should be my ranking in JEE(Adv) for such study? l am a General candidate.
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Hello,
According to JEE Advanced 2019 the cut off rank for Biotechnology was 6312 for general category candidates.The cut off score depends on a variety of factors and may change every year.Check out the link below for more details :
https://engineering.careers360.com/articles/jee-advanced-cutoff-for-iit-kharagpur
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