Hi!
Solution of your query is given below :
Work done by matthews and Noel in 63 days = [(1/63)*27]= 3/7
Remaining work = 1-3/7 =4/7
Now, 4/7 work is done by Noel in 60 days
Therefore, whole work will be done by Noel in 60*(7/4)= 105 days
Hope it helped to clear your delimma.
Question : A and B together can complete a project in 30 days. They started together, but after 6 days, A left the work and the work was completed by B after 36 more days. Single person A can complete the entire work in how many days?
Option 1: 45 days
Option 2: 90 days
Option 3: 60 days
Option 4: 120 days
Question : A and B together can complete a project in 10 days. They started together, but A left after 2 days and the remaining work was completed by B in 12 days. In how many days can A complete the entire work while working alone?
Option 1: 15 days
Option 2: 20 days
Option 3: 30 days
Option 4: 45 days
Question : A can complete some work in 35 days and B can complete the same work in 15 days. They worked together for 8 days, then B left the work. In how many days will A alone complete 60% of the remaining work?
Option 1: 15
Option 2: 10
Option 3: 5
Option 4: 8
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