NIT Kolkata All Questions

Hello Kanhaiya kumar..

According to careers360 rank formula, 

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 2,49,661.

As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.

So according to expected rank of yours, so you may or may not be eligible for jee advanced as we can't predict category rank and it is on edge.

So don't worry prepare well and write april jee mains well. best of the two exams will be considered.

Hope this helps you. All the best

Hello Harshavardhan..we can't predict marks as it is percentile, but we can predict the rank.

According to careers360 rank formula, 

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 3,98,273.

As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.

So according to expected rank of yours, so you are not eligible for jee advanced.

So don't worry prepare well and write april jee mains well. best of the two exams will be considered.

Nit cutoff will not be released now, you need to wait till april exam result.

Hope this helps you. All the best

It depends on how many students are secured percentile between your percentile and 100 percentile and also on April jee so wait 

Hello

Greetings

Your percentile is 93.734 It means 93.734% student of the Total student appeared for the Exam are Behind You Therefore 6.266% students of the Total students appeared for the exam are Ahead of You, Therefore Your calculated rank is 54794.2

Your Rank would change Either Your Percentile Score is Increases in the next attempt or Number of Student increases in the Next attemptIf the Number of Student Increases to 1400000 and Your percentile remain same then Your New rank would be 87724

As per Your current Performance You may be eligible for JEE Advance But the final cutoff will be released once the JEE Main April gets Over

If Your Percentile Score Increases in the Next attempt Then Your Rank would Be calculated By the Following Formula

 (100 - your total percentile score (Higher of two)) X Student appeared in JEE Main/100

You can Use the college Predictor to know about  the possible colleges in which You may get admission by Just following the link given below

https://engineering.careers360.com/jee-main-college-predictor

 At this rank It is Not possible to get admission into any NIT, Please try better in the next attempt of JEE Main

 You should Try to get more than 98 percentile for NIT

Hope this Helps All the Best

Hi Nandini,

Since the next round of JEE Main Exam is going to be held in April, only after which the final results including the cutoffs, percentiles and ranks, for all categories, will be announced; I advice and also request you to kindly wait till April 30th. 

Predicting whether you are eligible for any NIT based on your percentile is very tough because cutoffs and percentiles are very relative, that is, it keeps changing by a margin every year. Therefore, kindly wait for proper results.

I hope this helps you understand the result process better and clarifies your query. All the very best!

Our team is constantly researching and publishing the latest news relating to JEE Mains, therefore, kindly keep an active check on the platform. And I too will personally let you know of any updates. 

Hello

Greetings

Your percentile is 59.55It means 59.55% student of the Total student appeared for the Exam are Behind You Therefore 40.45% students of the Total students appeared for the exam are Ahead of You, Therefore Your calculated rank is 353723

Your Rank would change Either Your Percentile Score is Increases in the next attempt or Number of Student increases in the Next attempt, If the Number of Student Increases to 1400000 and Your percentile remain same then Your New rank would be 566300

Your rank is Not Good and You should Try in the Next attempt of JEE Main which is JEE Main April and Try to perform well

If Your Percentile Score Increases in the Next attempt Then Your Rank would Be calculated By the Following Formula

 (100 - your total percentile score (Higher of two)) X Student appeared in JEE Main/100

 At this rank It is Not possible to get admission into any NIT, Please try better in the next attempt of JEE Main

 You should Try to get more than 98 percentile for NIT

Hope this Helps All the Best

Hiii

Your expected rank will be around 6039. The score of 99.3093570 percentile is a quite good score. The cutoffs for NITs are yet to be released so i can not exactly say whether you can secure a seat or not but as per the previous trends, you have a great chance to get into NITs.
Talking about IITs, the admission to IITs is not depending on JEE mains. For IITs you need to qualify JEE Advance, and as per your mains score, you will surely be eligible for JEE Advance.
Still for the confirmation we need to wait for the final results to be declared.

Hope this helps

Thanks!!

Hello

Greetings

Congratulations!!! Right Now Your rank is 20990

but Your Rank may change Either Your Percentile Score is Increases in the next attempt or Number of Student increases in the Next attempt the Number of Student Increases to 1400000 and Your percentile remain same then Your New rank would be 33605

Your rank is Good and There are chances that You will get NIT or GOOD government college but CS in Top NIT is not Possible.

If Your Percentile Score Increases in the Next attempt Then Your Rank would Be calculated By the Following Formula

 (100 - your total percentile score (Higher of two)) X Student appeared in JEE Main/100

You can Use the college Predictor to know about the possible colleges in which You may get admission by Just following the link given below

https://engineering.careers360.com/jee-main-college-predictor

Hope this Helps All the Best

Hello Payal Cut-off for NIT will be out soon. However, the expected qualifying marks for NIT this year would be: General- 115 OBC-80 SC-60 ST