NIT Srinagar All Questions

Dear check kro phle it was 218372 closing rank of chemical eng branch ...see first ...search NIT srinagar in this app then check cutoff of state quota

Hello nida,
As per your marks your predicted rank will be less than 31000,so as per your home quota preferences your chances are fair enough to get nit srinagar.
You may also take a look over this for more insights.
https://dqxeclau.top/college-predictor
All the best.

Hello,
If you are a student of general or obc category then it is not possible to get admission in NIT SRINAGAR.So, prepare for the final paper and try to get high marks in jee mains.
Good luck.

hello aspirant,
firstly, i suggest you to come out of from query regarding which colleges we can get so that what are the main topics we will study.
it is a highly very wrong thinking,  so i will suggest you the best information so that you will be understanding what should be the answer
see, not only studying related topics is not important, but any college you can get if you score high marks and high rank based on your category.
i will provide you some of the important topics in each subject which will help you to crack the exam and go for further counsellings in order to get  admission in your desired college
regarding subjects and important topics and their  weightage,  prepare accordingly the topic which has more weightage in marks.
go through below link
JEE Main 2019 - Preparation Tips, Important Topics & Books
https://engineering.careers360.com  ...
go through it,  practice well sure you will crack and get admission in your desired college and particular stream.
thank you

Hi there.

The final cut off list will be declared by NTA after the April session of the JEE mains examination.

As for now, your probable rank can be calculated. 

Now, A total of 874469 candidates wrote the exam. Since the percentile is calculated from a scale ranging from 100 to 0 for each session of examinees, the formula applies the total number of students in the January session which is 874469 /100 multiplied by the percentage of people who are ahead of you to arrive at the rank.

Therefore, the formula to calculate the JEE Main 2019 rank for January 2019 is

JEE Main 2019 rank (probable) = (100-80.9) X 874469 /100 = 167023(approximately)


This rank may inflate or deflate depending on the total number of candidates who write the examination. in the April session. 

You could take a probable calculation and see where you stand. This means that you take a hypothetical number of the candidates who will appear in April. If you go by past trends, the figures are somewhat between 11 lakhs to 12 lakhs. Using this as a basis, use the NTA score and see which JEE Main rank you will get. 

Using the same formula,

If NTA percentile score is 80.9, JEE Main rank will be (100-80.9) X 1200000/100 = 229200

Now, using this estimated calculation, you can check previous year cut off trends and think of an idea of the probable colleges.

Check the following links for previous year trends in cut off :

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff/amp

For college predictor of JEE mains, check the link below:

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-college-predictor/amp

Hope this helps.
Good luck!