MAHE Manipal M.Tech 2025
ApplyNAAC A++ Accredited | Accorded institution of Eminence by Govt. of India | NIRF Rank #4
Hey!
NO, I really dont think modern ABC is the appropriate book for NEET prep… Though it can help you with the 12 grade exams.
For NEET-UG,
1st, For the KNOWLEDGE part -primarily you should go for NCERT first surely and after that for extra knowledge Allen packages or Trueman’s for biology would be more than sufficient.
2nd, For the APPLICATION part- buy sample paper books of previous years question papers to practice ,after retaining the theoretical content.
Apply ur knowledge in the questions…!!
Using distance formula d = sqrt((x2 - x1)^2 + (y2 - y1)^2) to find distance between two points A(x1, x2) and B(y1, y2), we can find the distance between A and B, B and C and A and C respectively.
We have, AB = sqrt((3-1)^2 + (5-k)^2)
= sqrt(2^2 + (5-k)^2
= sqrt(4 + (5-k)^2) (Equation 1)
BC = sqrt((6-3)^2 + (2-5)^2)
= sqrt(3^2 + (-3)^2)
= sqrt (18) (Equation 2)
AC = sqrt((6-1)^2 + (2-k)^2)
= sqrt(5^2 + (2-k)^2)
= sqrt((25 + (2-k)^2) (Equation 2)
Using Pythagoras theorem, we have AC^2 = AB^2 + BC^2
Substituting the values of AB, BC and AC from equation 1, 2 and 3 respectively, we have:
(sqrt((25 + (2-k)^2)) ^2 = (sqrt(4 + (5-k)^2)) ^2 + (sqrt (18))^2
= 25 + (2-k)^2 = 4 + (5-k)^2 + 18
= 25 + 4 + k^2 – 4k = 4 + 25 + k^2 -10k + 18
Rearranging and solving, we get, K = 3 (Answer)
Greetings Aspirant,
If the magnetic field along AB is B , the force acting on BC=F=BiL
Now the length of the side AC is Root"2L"
Also the current reverses the direction in this section as compared to that in BC.
Hence force on AC= Root"2"L( B× I )
= − Root"2"BILsin(45)
=−BIl=− F
If you are unable to understand the Answer I have uploaded an Image for Better Understanding.
https://drive.google.com/file/d/1e6gsucWKEXxS1si-XlTXIEmc11SRBq8K/view?usp=sharing
Hope My Answer Helped You.
Best Of Luck For Future.
Since A, B , C are the angles of a triangle and we know that the sum of all angles in a triangle is 180 degrees .
Consider A =5x
B=1x
C=6x
5x+1x+6x=180
12x=180
x=15 degrees
Angles A=5 X 15=75 degrees
B=15 degrees & C= 6X15= 90 degrees
By sine rule we know that (a/sinA)=(b/sinB)=(c/sinc)=2R
hence a=2RsinA, b=2RsinB, c=2RsinC
a:b:c=2RsinA : 2RsinB : 2RsinC
=sinA : sinB : sinC
=sin75 : sin15 : sin90
Hi
As per your question the solutions is:
It is for the reason that ΔABC ~ ΔPQR
We know that the corresponding sides of similar triangles are in proportion.∴ AB/PQ = AC/PR = BC/QR
...(i)
Also, ∠A = ∠P, ∠B = ∠Q, ∠C = ∠R …(ii)
Since AD and PM are medians, they may divide their contrary sides.∴ BD = BC/2 and QM = QR/2 ...(iii)
From equations (i) and (iii), we get
AB/PQ = BD/QM ...(iv)
In ΔABD and ΔPQM,
∠B = ∠Q [Using equation (ii)]
AB/PQ = BD/QM [Using equation (iv)]
∴ ΔABD ~ ΔPQM (By SAS similarity criterion)⇒ AB/PQ = BD/QM = AD/P
Hope helpful.
Hey there
You have good marks in your 10th and 12th but little low in your graduation so you need to get very good percentile in CAT for general category. CAT is all about speed so you have time in this lockdown you can speed up all the three sections specially quantitative analysis.
Check CAT cutoff in details
https://bschool.careers360.com/articles/cat-cutoff/amp
Good luck
Hello,
This question of construction is related to a triangle ABC.
The given perimeter of the triangle ABC is 75 cm,
If the perimeter is 75 cm, then it wouldn't form a triangle since side AC is very large. And if it is 7.5cm instead, even then, sum of two sides, AB and BC, is greater than the perimeter and hence, a triangle cannot be formed.
But if you wish to derive an answer from the given info, then since AB+BC= 10cm and the given perimeter of triangle ABC is = 75cm, side AC will be equal to 75-10 =65 cm.
Please check the values given in the question. You can repost the question with correct values on Careers360 to get the answer.
Hope this helps.
Thanks.
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