Dr KN Modi University, Tonk All Questions

Hi

This is easy, the answer is GHI

EXPLANATION

Let us number the each group of alphabets

LMN,    ABC,  OPQ,   DEF,  RST,   ______

1           2        3         4         5         6

You can observe that there is continuation of Alphabets in their normal order at alternate places

i. e we have LMN at 1st place, OPQ comes after LMN in the normal order which is nothing but your 3rd place. Similarly, we have ABC at 2nd place and DEF at 4th place , again we have OPQ at 3rd place and RST at 5th place.

Now,

We have to find alphabets at 6th place .

According to above pattern, Alphabets at 6th place will be

= next three alphabets of alphabets at alternate place of 6th i. e 4th place

= next three alphabets after DEF ( as DEF is at 4th place)

= GHI

So, 6th place /missing alphabets = GHI

Hence, the complete series is :-

LMN, ABC, OPQ, DEF, RST, GHI

If you have any other doubt then you can always reach us to clear them :) we are always available to help you out and guide you

Thank you

Please view this answer in Browser mode because the tables are not App friendly yet.

For any IIM, you will need more than 95 percentile. IIM A has had the following percentiles as the minimum cut offs for 2019 across all Categories.

Now the various ratings for various scores are as follows:

Now coming to the 12th, it looks like this for various Streams:

And then the Rating scores for Bachelor's degrees are as follows:

And for professional degrees, the rating scale looks like this:

And then work experience is considered too for those Candidates who have it. The scores from each level of studies are added up. And the no.of Candidates shortlisted per each Category will be as follows:

UR: 100

NC-OBC, Trans: 57

SC: 32

ST: 16

PWD: 6

And after being shortlisted based on these criteria, Candidates have to be shortlisted also for WAT and PI rounds. The whole process can be checked at their page: https://www.iima.ac.in/web/pgp/apply/domestic/admission/selection-process

IIM BANGALORE:

IIM B has a 2 phase selection process and the selection criteria are applied in 2 phases. For admission to IIM B, your CAT score alone is considered for finalizing  the first short list. Consistent good academic record starting from secondary school, higher secondary, Graduation etc are considered. Also CAT section wise scores are also considered along with relevant work experience. But CAT score is considered as the minimum level of proficiency that IIM -B expects from Candidates to be shortlisted. CAT 2019 cut offs for admission to batch of 2020-22 for IIM B were as follows:

During phase 1, all those Candidates shortlisted based on the cut offs will be called in for Personal Round of Interview. Here the panel will evaluate each Candidate based on Academic Background, quality of work experience, etc. Those who clear this round will have to take a Writing Ability Test. The topic will be given by IIM B. The topics might range from issues and developments related to socio-political, economic and business affairs, sports, etc which require your creative thinking. This round is approximately for 30 minutes. The Pre- PI, Interview and WAT scores will be used for second phase.

In phase 1, the Candidate's percentage scores in their 10th and 12th exams are adjusted by dividing each score by 90th percentile score obtained in that board. For this purpose, data base of CAT applicants of the past 2 years is considered. After this, an adjusted score is calculated based on the final score obtained in the Bachelor's degree. The final shortlisting weightage is as follows:

CAT = 40
10th board = 20
12th board = 10
Bachelors = 20
Gender Diversity = 2
Work Experience = 8

The 40 points for CAT are derived from the performance in each of the three sections as follows:
Verbal & Reading Comprehension - 14 points
Data Interpretation & Logical Reasoning - 16 points

Quantitative Aptitude - 10 points.

The WAT score with a weightage of 10 and the personal interview score with a weightage of  30, after standardization across interview panels and sessions, will be added for a final aggregate score. And that looks like this:

CAT (weight = 25)

10th board (weight = 10

12th board (weight = 5)

Bachelors (weight = 10)

Weighted Work Experience (weight = 10).

This answer covers pretty much everything regarding IIM B admission process. For any more information, please read the official article: https://www.iimb.ac.in/sites/default/files/inline-files/PGP-admission-process-2020-22.pdf

IIM Calcutta:

And the final selection is based on:
CAT 2020 Score 30
Personal Interview 48
Written Ability Test 10
Academic Diversity 04
Work Experience 08
Total 100

Hey there,

I hope you are safe and healthy.

I am providing you a link below. There you will find the answer to your question in a step-wise and a proper elaborative manner. I hope you understand the solution.

https://learn.careers360.com/ncert/question-using-the-method-of-integration-find-the-area-of-the-triangle-abc-coordinates-of-whose-vertices-are-a-2-0-b-4-5-and-c-6-3/

I hope you find it useful.

Hello student,

I hope you are doing well.

1). The three pairs of equal parts in two triangles ABC and BOD are:

CO = DO (given)

OA = OB (given)

Angle COA = Angle DOB ( As opposite angles are equal when two lines intersect)

2).  So by SAS congruency rule,

Triangle COA is congruent to Triangle DOB

that is

Triangle AOC is congruent to Triangle BOD

Hence, option B is correct.

I hope it helps.

Hi there,

I hope you are doing well. The language of your question is not clear but what I infer is that you have opted for wrong option and form has been submitted.

I would like to tell you that try contacting the concerned authority of the council to make changes in your form . Otherwise once the submission has done nothing will change .

Thank you

Hii Meghana,

It depends on the exam pattern . If the given question has partial marking then you will get partial marking in the above case . If there is no partial marking then you will loose marks, in some cases even there is a chance of negative marking also. It all depends on the pattern of the examination . so , refer the model of the question clearly while answering.

you can refer the below link for mock tests so that, you can get more awareness on examination -

https://engineering.careers360.com/articles/jee-advanced-mock-test

Hope you find the answer.

All the best !

Hello aspirant,

Hope you are doing well.

As per your question regarding ICAR exam if you are eligible for exam then definitely you can give the ICAR exam. Here Eligibility mainly concerns with that you should have passed 10+2 with a minimum percentage of 50 percentage as per general category as you didn't mentioned your category. Also if you belong from OBC you still need to have 50 percent aggregate in 12th while if you you belong to ST/SC you need minimum of 40 percent aggregate to be eligible in ICAR exam. So these are the eligibilty to give exams of ICAR if all fulfills then you can give this exams.

For more information and updates you can visit:-

https://www.google.com/amp/s/university.careers360.com/articles/icar-aieea/amp

Hope this helps you. Thank you.

Dear Julia ,

If you are join XYZ college and complete your 1st year course but if you will take admission in another college without informing XYZ college then it will trouble in future because you have already student of this college or university with particular registration number and it is one type of illegal work .So you should confirm to college and leave with the formalities then only you will not facing any trouble in future .

Hope it will helpful

Thanks

Hey Jaywadmare, the anwer of your question is 34/3.

Also go through following explanation.

Explanation : a^2 = d ^12

b^3 = d ^12

c^9 = d ^12

after that logd ( d^12) 1/2 + 1/3 + 1/9 = logd (d^12)^ 51/54

= logd (d ^12 * 17/18)

= 1 * 12 * 17/18

= 34/3.

I hope this will helps to you and thank you !!!

In a triangle ABC cos(A+B)= cosAcosB-sinAsinB. cos(A-B)= cosAcosB+sinAsinB.

there by, by adding these two and multiplying the result by 2 times you get the desired answer. 4cosAcosB = 2[cos(A+B) + cos (A-B)]. This can also be done by interchanging the signs and the answer will remain the same.