NIT Trichy All Questions

Hello aspirant,

I will mention the cutoff ranks of all branches in Nit,Trichy gor general cadte students-

• CSE- 1370
• ECE- 3019
• EEE- 5200
• MECHANICAL- 6000
• CHEMICAL- 10600
• METALLURGY- 16800
• CIVIL- 12500
• PRODUCTION- 19600
• INSTRUMENTATION- 13600

For more info regarding the cutoff ranks of NIT,Trichy go through this link-
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-nit-trichy/amp

Hi   Rina,

You got 98.65 percentile in JEE main 2 exam, your rank would be approximately in between 1500 to 2500.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check your expected rank using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 are 112680, your rank will be around 1500. However as the no. of students in April changes, your rank will change according to that. On the basis of your percentile, you will get NIT colleges:

National Institute of Technology, Tiruchirappalli

National Institute of Technology, Rourkela

National Institute of Technology Calicut

School of Planning & Architecture, Bhopal

School of Planning & Architecture: Vijayawada

You can also go through our college predictor to check which colleges you are eligible for through your JEE Mains score. The link for the college predictor is : https://engineering.careers360.com/jee-main-architecture-college-predictor

Sneha, You have not specified whether you want to inquire about your chances based on percentile secured in JEE MAIN PAPER-1 or JEE MAIN PAPER-2. So, I am going to answer your query taking into consideration that the query is about Paper2 and if your query was different, then you can let me know.

Now, to calculate your expected rank for B.Arch based on the percentile score that you have secured, you can use this formula:

So, (100 - your total percentile score) is the percentage of people ahead of you. Also, 112679 were the number of candidates who appeared for January exam.

Also,note that the ranks will change according to increase or decrease in the number of participants in the next session.

So rank formula is (100 - your total score) X 112679 /100.

Now, according to this formula, your expected rank is around 3560. The admission to any college also depends on your home state and category status and you have not given details about the same.In your case, your chances of getting NIT TRICHY are very small irrespective of your home state and gender as previous year closing rank for ALL INDIA quota for general category was 1075 and the closing rank for general category based on home state quota was 2468. So, going by previous years trends, your chances of making it to NIT THIRUCHIRAPALLI are very small.

If you want to check the previous year cutoffs, you can visit this link

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

However, you have a good percentile and it could give you admission to some other NITs and many other good private institutes and hence you should try for the same.

Also, if you want to predict your colleges using your scores, you can use this college predictor https://engineering.careers360.com/jee-main-architecture-college-predictor?ici=cp-listing_engineering&icn=JEE-Main-Architecture-College-Predictor

Hi Aahit,
You have not specified your category to which you belong.
According to your percentile your ranking will be as follows:
100-percentile obtained*896010/100
=3215
Previous year cutoff for architecture are as follows for all the categories:
OBC: 1043

General: 2468

SC: 271

ST: 746

EWS: 798
For more detailed information about cutoff you can visit the following website:https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-trichy/amp

Best wishes

HELLO GANESH
The colleges which are you talking about is referred as the college which comes under top 5 NITs so getting into this is very challenging job.
now according to my researches and the previous year cutoffs you should at least have a percentile of 99.6+ to get cs branch.

But you can do it with a proper strategy and hard work!!

HOPE IT HELPS!! BEST OF LUCK !!

Hello,

Yeah, he would get a seat for sure if he clear advance also..!
But their are chances where he can get with percentage also...! It all depends on the cut off..

Thank you..!

Hello,
It is hard to predict the percentile as it depends on number of candidates appeared and the percentage of candidates who score equal or less marks than you.
However, you calculate your expected rank using the formula and then you can check the cut off rank for NIT, Trichy and compare with your rank.
Your expected rank can be calculated using the formula
(100-your total percentile)*112679/100
Where 112679 is the total number of candidates appeared in January session.
Check the previous year cut off for NIT, Trichy category wise.The ranks are opening and closing rank respectively

• General category: 765-1550(home state), 436-670 (other state)
• OBC-NCL: 280-577 (home state), 156-319 (other state)
• SC: 117-273(home state), 69-152( other state)
• ST: 274-596(home state), 23-42( other state)

However, cut off is subjected to change it may increase or decrease slightly.

Hi,

Admission to Undergraduate Engineering/Architecture Programs for the candidates from India at NITs, IIITs, Other centrally funded Technical Institutions shall include the performance in the class 12/other Qualifying Examination and in the Joint Entrance Examination, JEE (Main).

For more details visit What is the minimum score in b arch exam to get a seat in NIT Trichy?? - Careers360

Hope this helps.

Hello Muthu,

You haven't mentioned your home state and category,interested department . So I'm giving you cut offs of Last year.You have to get AIR less than 10,000 to get any department except CSE. To know the branches wise cutoff you can go through with the given below link.

https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-trichy

According to the percentile you have to get above 95, to get into NIT trichy. And you can calculate your approximate rank with the formula:100 - your total percentile score is the percentage  of people ahead of you. 869010 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100.  Calculate your approximate rank with this.

Hello,
In 2019 a candidate belonging to SC category (home state-female) with rank 525 secured a seat in NIT, Tiruchirapalli. But it is hard to predict the percentile because it depends on number of candidates appeared in the exam, highest and lowest marks scored in the exam.But to get such rank you may need to have a percentile above 90 to have good chances.